Comments on: Bourne/bash shell scripts: case statement

By: Ocho

Ocho — Fri, 27 Jan 2012 19:30:35 +0000

read input
case “${input}” in
y|Y|yes|YES|Yes)
echo “Do some yes things…”
;;
n|N|no|NO|No)
echo “Do some no things”
;;
*)
echo “${input} is not a valid input. ”
# loop back in via a function or return 1 or quit etc.
;;
esac

By: Sony Sebastian

Sony Sebastian — Wed, 19 Jan 2011 17:43:00 +0000

#!/bin/sh

echo “Enter your choice:”
read username

case “$username” in
’start’)
echo ’starting…………’;;
’stop’)
echo ’stopping………..’;;
‘restart’)
echo ‘restarting………’;;
esac

##################
Output:
./test.sh

Enter your choice:
start
starting…………

By: Garry Hurley Jr

Garry Hurley Jr — Mon, 11 Oct 2010 16:27:00 +0000

Simple. You need to use the escape character on the switch, and you escape it as a parameter. Here is a basic example of that line

#!/bin/bash
case $1 in
%)
echo “%”
;;
*)
echo “*”
;;
*)
echo “none of the above”
;;
esac

Sample output:

snoopy:~>./testBash *
*

My suggestion is to use the ‘x’ for multiplication instead if you don’t want your users to have to escape the ‘*’ every time they use the program.

By: Mark

Mark — Sun, 28 Mar 2010 14:37:00 +0000

Thanks!

By: Patrick

Patrick — Fri, 05 Mar 2010 20:23:00 +0000

Nice this one was really usefull, but the last one didn’t seem to work for me.
It would whine about a syntax error, so I removes the ! in front and added a *) to catch all the rest, in the case I just did a echo “parameter is valid”

But thanx a lot

By: S.Raghu

S.Raghu — Sat, 13 Jun 2009 07:56:00 +0000

How to branch if the value of the variable is ‘*’ ?
For eg parameters passed to a program are 2 numbers and an arithmetical operand.

By: newbie

newbie — Tue, 21 Apr 2009 04:29:00 +0000

stdin means “standard input” from the keyboard (file descriptor=0)
stdout means “standard output” to the computer screen (file descriptor=1)
stderr means “standard error”; output for error messages (file descriptor=2)

By: Anonymous

Anonymous — Wed, 31 Dec 2008 09:28:00 +0000

case “$1″ in
stdin|
-)
commands
;;

What does stdin|
-) mean here?
Can somebody explain it?